document.write( "Question 226639: What quantity of 75 per cent acid solution must be mixed with a 30 percent solution to produce 1215 mL of a 50 per cent solution? \n" ); document.write( "
Algebra.Com's Answer #168726 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .75x+.30(1215-x)=.50*1215 \n" ); document.write( ".75x+364.5-.30x=607.5 \n" ); document.write( ".75x-.30x=607.5-364.5 \n" ); document.write( ".45x=243 \n" ); document.write( "x=243/.45 \n" ); document.write( "x=540 ml of 75% acid. \n" ); document.write( "1215-540=675 ml of 30% acid. \n" ); document.write( "Proof: \n" ); document.write( ".75*540+.30*675=.50*1215 \n" ); document.write( "405+202.5=607.5 \n" ); document.write( "607.5=607.5\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |