document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=225799>Question 225799</A>: <I><SPAN STYLE=\"word-break: break-all;\"> given tangent of theta is 2. use trigonometric identities to find the exact value of cot( 90 degreess minus theta).\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #168720 by </B><A HREF=/tutors/aboutme.mpl?userid=chibisan><B>chibisan(131)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=chibisan><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=chibisan><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=168720\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> lets make theta as A<BR>\n" );
document.write( "tanA =2                                                <BR>\n" );
document.write( "so tan is positive is so it lies on the 1st quadrant   \r<BR>\n" );
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document.write( "Simplify cot(90°-A)<BR>\n" );
document.write( "cos(90°-A)/sin(90°-A)<BR>\n" );
document.write( "=cos90°cosA+sin90°sinA / sin90°cosA-cos90°sinA<BR>\n" );
document.write( "=sinA/cosA<BR>\n" );
document.write( "=tanA\r<BR>\n" );
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document.write( "so, finally , tanA = 2 </SPAN>\n" );
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