document.write( "Question 226628: The length of of a rectangle is 15ft more than its width. Find its dimension, if the perimeter is 322ft \n" ); document.write( "
Algebra.Com's Answer #168717 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! L=W+15 \n" ); document.write( "2L+2W=322 \n" ); document.write( "2(W+15)+2W=322 \n" ); document.write( "2W+30+2W=322 \n" ); document.write( "4W=322-30 \n" ); document.write( "4W=292 \n" ); document.write( "W=292/4 \n" ); document.write( "W=73 ANS. FOR THE WIDTH. \n" ); document.write( "L=73+15=88 ANS. FOR THE LENGTH. \n" ); document.write( " \n" ); document.write( " |