document.write( "Question 226335: solving the equation.check your solution\r
\n" ); document.write( "\n" ); document.write( "-5(2y+3-5=-4(y+8)+2\r
\n" ); document.write( "\n" ); document.write( "what do I do first?
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Algebra.Com's Answer #168711 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
-5(2y+3)- 5 = -4(y+8) + 2
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\n" ); document.write( "Do what is necessary to get the variable (y) on one side by itself
\n" ); document.write( "Usually on the left, but doesn't have to be
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\n" ); document.write( "Multiply what inside the brackets (distribute)
\n" ); document.write( "-10y - 15 - 5 = -4y - 32 + 2
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\n" ); document.write( "do the math
\n" ); document.write( "-10y - 20 = -4y - 30
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\n" ); document.write( "Add 4y to both sides
\n" ); document.write( "-10y + 4y - 20 = -30
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\n" ); document.write( "add 20 to both sides
\n" ); document.write( "-10y + 4y = -30 + 20
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\n" ); document.write( "combine like terms
\n" ); document.write( "-6y = -10
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\n" ); document.write( "The variable (y) has to be positive, multiply both sides by -1
\n" ); document.write( "6y = 10
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\n" ); document.write( "Divide both sides by 6
\n" ); document.write( "y = \"10%2F6\"
\n" ); document.write( "y = \"5%2F3\"
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\n" ); document.write( "Check the solution by replacing y with 5/3 in the original equation
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