document.write( "Question 226385: A commercial building was built in 1 - 7/8 months by 20 skilled workers and 30 unskilled laborers. If 30 skilled men were contracted the group alone would have erected the facility in 2 months time, How long should it take one unskilled worker alone to complete the job?
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Algebra.Com's Answer #168705 by ankor@dixie-net.com(22740)\"\" \"About 
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A commercial building was built in 1 - 7/8 months by 20 skilled workers and 30 unskilled laborers.
\n" ); document.write( "If 30 skilled men were contracted the group alone would have erected the facility in 2 months time,
\n" ); document.write( "How long should it take one unskilled worker alone to complete the job?
\n" ); document.write( "Find the time required by one skilled worker
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\n" ); document.write( "It says, \"Two months with 30 skilled workers only\"
\n" ); document.write( "that's 60 man/months (skilled) to complete the job
\n" ); document.write( "Therefore one man requires 60 months to do the job
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\n" ); document.write( "Then 20 skilled men: 60/20 = 3 months to do the same job
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\n" ); document.write( "Change 1\"7%2F8\" to 1.875 months\r
\n" ); document.write( "\n" ); document.write( "Let u = the time required by 30 unskilled workers
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\n" ); document.write( "Let the completed job = 1
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\n" ); document.write( "Skilled + unskilled = completed job
\n" ); document.write( "\"1.875%2F3\" + \"1.875%2Fu\" = 1
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\n" ); document.write( "Multiply equation by 3u
\n" ); document.write( "1.875u + 3(1.875) = 3u
\n" ); document.write( "5.625 = 3u - 1.875u
\n" ); document.write( "5.625 = 1.125u
\n" ); document.write( "u = \"5.625%2F1.125\"
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\n" ); document.write( "u = 5 months using 30 unskilled men
\n" ); document.write( "therefore
\n" ); document.write( "5*30 = 150 man/months (unskilled) to do the job
\n" ); document.write( "therefore:
\n" ); document.write( "150 months for one unskilled man to do the job
\n" ); document.write( "and
\n" ); document.write( "60 months for one skilled man to do it
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\n" ); document.write( "Check solution:
\n" ); document.write( "\"1.875%2F3\" + \"1.875%2F5\" = 1
\n" ); document.write( ".625 + .375 = 1
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