document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=30181>Question 30181</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Simplify by combining like terms.  V is used for the square root symbol.\r<BR>\n" );
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document.write( "V63 - 2V28 + 5V7\r<BR>\n" );
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document.write( "Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #16870 by </B><A HREF=/tutors/aboutme.mpl?userid=ikdeep><B>ikdeep(226)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ikdeep><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ikdeep><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=16870\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> V63 - 2V28 + 5V7\r<BR>\n" );
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document.write( "make factors of values which are inside the root ,,,and we get \r<BR>\n" );
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document.write( "V3*3*7 - 2V2*2*7 + 5V7\r<BR>\n" );
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document.write( "Now u know that the for every two same numder inside the square root we get one of that num outside the squareroot,,,so we get ...\r<BR>\n" );
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document.write( "3V7 - 2*2V7 + 5V7\r<BR>\n" );
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document.write( " = 8V7 - 4V7 \r<BR>\n" );
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document.write( " = 4V7\r<BR>\n" );
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document.write( "hope this will help you \r<BR>\n" );
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document.write( "Please feel free to revert back for any further queries.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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