document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=226581>Question 226581</A>: <I><SPAN STYLE=\"word-break: break-all;\"> you have 40 seats and 137 legs. By making chairs and 3- legged stools, how many of each can be made? But having no left overs </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #168690 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=168690\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let  c= # chairs(4 legs),,,,,,and  s=# stools  (3 legs)<BR>\n" );
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document.write( "c+s = 40,,or c=40-s,,,number  of  seats,,,,1  seat  each  for  chair  or  stool<BR>\n" );
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document.write( "4*c +3*s = 137,,,,,,,,total  number  of  legs<BR>\n" );
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document.write( "subst,,,,4(40-s) +3s = 137<BR>\n" );
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document.write( "160 -4s +3s =137<BR>\n" );
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document.write( "160-137 = 4s-3s<BR>\n" );
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document.write( "23 = s,,,,,,,,,c=40-s,,,,,c= 40-23 = 17<BR>\n" );
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document.write( "check,,,,3*23 +4*17 = 69 +68 = 137,,,,ok<BR>\n" );
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