document.write( "Question 30193: Solve by using the Gaussian elimination method. For instance: \r
\n" ); document.write( "\n" ); document.write( " 5x+2y=3
\n" ); document.write( " 3x+4y=13\r
\n" ); document.write( "\n" ); document.write( "I seem to always get stuck on the fractions. Please help in details so I know how to solve more problems like this. Thank You.
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Algebra.Com's Answer #16869 by ikdeep(226)\"\" \"About 
You can put this solution on YOUR website!
5x+2y=3............(1)\r
\n" ); document.write( "\n" ); document.write( "3x+4y=13............(2)\r
\n" ); document.write( "\n" ); document.write( "For elimination we need one variable in both equation to be equal,,,but here we dnt have that,,,so further solution is done in the following ways...\r
\n" ); document.write( "\n" ); document.write( "Multiply (1) by 3 and you get ...
\n" ); document.write( "15x + 6y = 9............(3)\r
\n" ); document.write( "\n" ); document.write( "Multiply (2) by 5 and you get
\n" ); document.write( "15x + 20y = 65............(4)\r
\n" ); document.write( "\n" ); document.write( "Now , by elimination method and subtract (4) from (3)and we get...\r
\n" ); document.write( "\n" ); document.write( "15x + 6y = 9............(3)
\n" ); document.write( "15x + 20y = 65............(4)
\n" ); document.write( "- - -
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\n" ); document.write( " - 14y = -56 (15x in both eqautions would be eliminated)
\n" ); document.write( " or y = -56/-14
\n" ); document.write( " y = 4\r
\n" ); document.write( "\n" ); document.write( " now, substitute the value of y in any of the equation to get the value of x here I am taking (2)...\r
\n" ); document.write( "\n" ); document.write( "3x+4y=13............(2)
\n" ); document.write( "putting the values of y = 4 ,,we get\r
\n" ); document.write( "\n" ); document.write( "3x + 4 * 4 = 13\r
\n" ); document.write( "\n" ); document.write( "3x + 16 = 13\r
\n" ); document.write( "\n" ); document.write( "3x = 13 - 16 \r
\n" ); document.write( "\n" ); document.write( "3x = -3 \r
\n" ); document.write( "\n" ); document.write( "x = -3/3\r
\n" ); document.write( "\n" ); document.write( "x = -1\r
\n" ); document.write( "\n" ); document.write( "Now if you wanna verify you answer ,,,you can put the values of x and y in any of the equation and if you get LHS=RHS,,,this means that you answer is correct..\r
\n" ); document.write( "\n" ); document.write( "hope this will help you \r
\n" ); document.write( "\n" ); document.write( "Please feel free to revert back for any further queries.\r
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