document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=226578>Question 226578</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The surface area s of a right prism is given by <BR>\n" );
document.write( "s=2b+p h<BR>\n" );
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document.write( "where b is the area of the base, p is the perimeter of the base, and h is the height of the prism. <BR>\n" );
document.write( "Solve for b . <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #168689 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=168689\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> s = 2b + ph,,,,,,subtract ph  both  sides <BR>\n" );
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document.write( "s-ph = 2b,,,,,,,,,,divide  both  sides  by  2<BR>\n" );
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document.write( "(s-ph)/2 =b<BR>\n" );
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document.write( "check,,,,s= 2(s-ph)/2 +ph  = s-ph +ph =s,,,,,,,ok<BR>\n" );
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