document.write( "Question 226573: if a certain two digit number is divided by the sum of its digits, the quotient is 3. if the digits are reversed, the new number is 9 less then three times the original number. find the original number.\r
\n" ); document.write( "\n" ); document.write( "I think i have one of the equations: I used Z as my new number and X as the original number. Z=3X-9
\n" ); document.write( "could you help me solve this using a set of system of equations?\r
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Algebra.Com's Answer #168686 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let x = original number and y = reversed number\r
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\n" ); document.write( "\n" ); document.write( "Any two digit number is of the form \"x=10t%2Bu\". Ex: 21=10*2+1 (think of t is the tens digit and u as the units/ones digit)\r
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\n" ); document.write( "\n" ); document.write( "So \"x=10t%2Bu\" and \"y=10u%2Bt\" (just swap t and u)\r
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\n" ); document.write( "\n" ); document.write( "The statement \"if a certain two digit number is divided by the sum of its digits, the quotient is 3\" translates to \"x%2F%28t%2Bu%29=3\" (because t+u is the sum of the digits). Plug in \"x=10t%2Bu\" to get \"%2810t%2Bu%29%2F%28t%2Bu%29=3\". So this is our first equation.\r
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\n" ); document.write( "\n" ); document.write( "\"if the digits are reversed, the new number is 9 less then three times the original number\" translates to \"y=3x-9\". Plug in \"x=10t%2Bu\" and \"y=10u%2Bt\" to get \"10u%2Bt=3%2810t%2Bu%29-9\". This is the second equation.\r
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\n" ); document.write( "\n" ); document.write( "So you now have the system \"system%28%2810t%2Bu%29%2F%28t%2Bu%29=3%2C10u%2Bt=3%2810t%2Bu%29-9%29\"\r
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\n" ); document.write( "\n" ); document.write( "Because you have two equations with two unknowns, you can find the unique solution which means you can find t and u. I'll let you do that. Let me know if you still need help.
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