document.write( "Question 226557: Solve by using square root property:\r
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Algebra.Com's Answer #168677 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\"%288x-3%29%5E2=25\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"8x-3=%22%22%2B-sqrt%2825%29\" Take the square root of both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"8x-3=sqrt%2825%29\" or \"8x-3=-sqrt%2825%29\" Break up the \"plus/minus\" to form two equations.\r
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\n" ); document.write( "\n" ); document.write( "\"8x-3=5\" or \"8x-3=-5\" Take the square root of \"25\" to get \"5\".\r
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\n" ); document.write( "\n" ); document.write( "\"8x=3%2B5\" or \"8x=3-5\" Add \"3\" to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"8x=8\" or \"8x=-2\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"x=1\" or \"x=-1%2F4\" Divide both sides by \"8\" to isolate \"x\".\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"x=1\" or \"x=-1%2F4\".
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