document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=30144>Question 30144</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help:<BR>\n" );
document.write( "2x^2+3x=20\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #16865 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=16865\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Rewrite the equation as 2x~2+3x-20=0.\r<BR>\n" );
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document.write( "The factors of 2 are 1&2, the factors of 20 are 1,2,4,5,10,&20.\r<BR>\n" );
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document.write( "Because the number is - one number must be = & the other one -.\r<BR>\n" );
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document.write( "The combinations or multiplying 1&2 to each set of factors of 20 must have a difference of 3. The only combination is (1x+5)&(2x-4)or 5-8= -3\r<BR>\n" );
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document.write( "Therefore the factors are(x-4)x(2x+5). x times 2x=2x~2<BR>\n" );
document.write( "                                       -4 times 2x=-8x<BR>\n" );
document.write( "                                       x times 5=5x<BR>\n" );
document.write( "                                       -4 times 5=20<BR>\n" );
document.write( "2x~2-8x+5x-20=0<BR>\n" );
document.write( "2x~2-3x-20=0 <BR>\n" );
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