document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=226502>Question 226502</A>: <I><SPAN STYLE=\"word-break: break-all;\"> twice one number plus a second number is 42, and the first number minus the second number is -6, find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #168631 by </B><A HREF=/tutors/aboutme.mpl?userid=user_dude2008><B>user_dude2008(1862)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=user_dude2008><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=168631\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \"twice one number plus a second number is 42,\" ---> 2x+y=42 ---> y=-2x+42\r<BR>\n" );
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document.write( "\"the first number minus the second number is -6\" --> x-y=-6 \r<BR>\n" );
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document.write( "x-y=-6 \r<BR>\n" );
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document.write( "x-(-2x+42)=-6 \r<BR>\n" );
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document.write( "x+2x-42=-6\r<BR>\n" );
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document.write( "3x=36\r<BR>\n" );
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document.write( "x=12 <---- first number\r<BR>\n" );
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document.write( "y=-2(12)+42=-24+42=18 <---- second number\r<BR>\n" );
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