document.write( "Question 226500: logx-log(x-1)=2 \n" ); document.write( "
Algebra.Com's Answer #168630 by user_dude2008(1862)\"\" \"About 
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log(x)-log(x-1)=2\r
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\n" ); document.write( "\n" ); document.write( "log(x/(x-1))=2\r
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\n" ); document.write( "\n" ); document.write( "10^2=x/(x-1)\r
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\n" ); document.write( "\n" ); document.write( "100(x-1)=x\r
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\n" ); document.write( "\n" ); document.write( "99x=100\r
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\n" ); document.write( "\n" ); document.write( "x=100/99 <---- Answer
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