document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=226461>Question 226461</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the polar form of the following expression: 3 sq root 2 - 3 sq root 2i?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #168617 by </B><A HREF=/tutors/aboutme.mpl?userid=user_dude2008><B>user_dude2008(1862)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=user_dude2008><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=168617\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE z=3\sqrt{2}-3\sqrt{2}i \Rightarrow x=3\sqrt{2}, y=-3\sqrt{2}\">\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE r=\|z\|=\sqrt{x^2+y^2}=\sqrt{\left(3\sqrt{2}\right)^2+\left(-3\sqrt{2}\right)^2}=\sqrt{18+18}=\sqrt{36}=6\">. <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE r=6\">\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \theta=\tan^{-1}\left(\frac{y}{x}\right)=\tan^{-1}\left(\frac{-3\sqrt{2}}{3\sqrt{2}}\right)=\tan^{-1}(-1)=-\frac{\pi}{4}\">\r<BR>\n" );
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document.write( "Polar Form: <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE z=r\left(\cos\left(\theta\right)+i\sin\left(\theta\right)\right)=6\left(\cos\left(-\frac{\pi}{4}\right)+i\sin\left(-\frac{\pi}{4}\right)\right)=6\left(\frac{\sqrt{2}}{2}-i\frac{\sqrt{2}}{2}\right)\">\r<BR>\n" );
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document.write( "Answer: Polar form of <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE z=3\sqrt{2}-3\sqrt{2}i\"> is <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE  6\left(\frac{\sqrt{2}}{2}-i\frac{\sqrt{2}}{2}\right)\">\r<BR>\n" );
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