document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=3854>Question 3854</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Im trying to do my homework, but I dont understand it.\r<BR>\n" );
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document.write( "It says y=x(squared)+1\r<BR>\n" );
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document.write( "and to find the<BR>\n" );
document.write( "Y-intercept:<BR>\n" );
document.write( "X-Intercept:<BR>\n" );
document.write( "Vertex:<BR>\n" );
document.write( "axus of symmetry:\r<BR>\n" );
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document.write( "Thanks. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #1686 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=1686\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the y-intercept is where x=0, we then get y=1. Done!\r<BR>\n" );
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document.write( "the x-intercept(s) is/are where y=0, so we get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2B1+=+0 ALIGN=MIDDLE  ALT=\"x%5E2%2B1+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" >. Re-arranging, we get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2+=+-1 ALIGN=MIDDLE  ALT=\"x%5E2+=+-1\"   DISABLED_style= \"max-width:90%; height:auto;\" >, so x= +-<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28-1%29 ALIGN=MIDDLE  ALT=\"sqrt%28-1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >. For this, you need to know Complex numbers. As far as you are concerned, there are no answers ie the curve does not cross the x-axis.\r<BR>\n" );
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document.write( "differentiate, to give dy/dx = 2x.\r<BR>\n" );
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document.write( "The turning point (vertex) is where the gradient (dy/dx) is zero, so ask this of th eequation: 2x=0 --> x=0. And y at this point?. It is y=1 (we already found the point earlier).\r<BR>\n" );
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document.write( "So, the vertex is at (0,1). The axis of symmetry always goes through the turning point, so axis is the y-axis, whose equation is x=0.\r<BR>\n" );
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document.write( "Just, so you can see it, here is the graph:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=graph%28100%2C100%2C-4%2C4%2C0%2C10%2Cx%5E2%2B1%29 ALIGN=MIDDLE  ALT=\"graph%28100%2C100%2C-4%2C4%2C0%2C10%2Cx%5E2%2B1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "jon.<BR>\n" );
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