document.write( "Question 226400: give the equation of the line that passes thru (0.9,0.3) and parallel to 3x+2y=6, leave your answer in y=mx+b form \n" ); document.write( "
Algebra.Com's Answer #168595 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
slope-intercept form of the equation of a line is y = mx = b where m is the slope and b is the y-intercept.\r
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\n" ); document.write( "\n" ); document.write( "equation of 2x + 2y = 6 is the standard form of the equation of a line.\r
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\n" ); document.write( "\n" ); document.write( "That standard form is ax + by = c\r
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\n" ); document.write( "\n" ); document.write( "You need to convert that equation to the slope intercept form first.\r
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\n" ); document.write( "\n" ); document.write( "2x + 2y = 6 is the original equation.
\n" ); document.write( "subtract 2x from both sides of the equation to get:
\n" ); document.write( "2y = -2x + 6
\n" ); document.write( "divide both sides of the equation by 2 to get:
\n" ); document.write( "y = -x + 3\r
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\n" ); document.write( "\n" ); document.write( "your original equation in slope-intercept form is:\r
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\n" ); document.write( "\n" ); document.write( "y = -x + 3\r
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\n" ); document.write( "\n" ); document.write( "The slope of your original equation is -1.\r
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\n" ); document.write( "\n" ); document.write( "Your equation will have the same slope.\r
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\n" ); document.write( "\n" ); document.write( "take the general slope-intercept form of:\r
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\n" ); document.write( "\n" ); document.write( "y = mx + b\r
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\n" ); document.write( "\n" ); document.write( "and replace m with -1 to get:\r
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\n" ); document.write( "\n" ); document.write( "y = -x + b\r
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\n" ); document.write( "\n" ); document.write( "now take your points of (x,y) = (.9,.3) and replace x and y in this equation with them.\r
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\n" ); document.write( "\n" ); document.write( "you get:\r
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\n" ); document.write( "\n" ); document.write( "y = -x + b becomes:
\n" ); document.write( ".3 = -.9 + b
\n" ); document.write( "add .9 from both sides of this equation to get:
\n" ); document.write( ".3 + .9 = b
\n" ); document.write( "simplify to get:
\n" ); document.write( "b = 1.2\r
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\n" ); document.write( "\n" ); document.write( "replace b in the slope-intercept form of your equation to get:\r
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\n" ); document.write( "\n" ); document.write( "y = -x + 1.2\r
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\n" ); document.write( "\n" ); document.write( "That should be your equation.\r
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\n" ); document.write( "\n" ); document.write( "Graph the original equation and your equation to show as follows:\r
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\n" ); document.write( "\n" ); document.write( "\"graph%28600%2C600%2C-4%2C4%2C-4%2C4%2C-x%2B3%2C-x%2B1.2%2C.9%29\"\r
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\n" ); document.write( "\n" ); document.write( "The horizontal line at y = .9 shows you that this occurs on your parallel line at around x = .3\r
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