document.write( "Question 226395: if a basketball player has a vertical leap of about 20 inches. what is his hang time?use the hang-time function v=48t^2 \n" ); document.write( "
Algebra.Com's Answer #168594 by nerdybill(7384)\"\" \"About 
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The problem gives you:
\n" ); document.write( "v=48t^2
\n" ); document.write( "where
\n" ); document.write( "v is \"vertical leap\" (in inches)
\n" ); document.write( "t is time (in seconds)
\n" ); document.write( ".
\n" ); document.write( "Plug in the given \"vertical leap\" of 20 inches and solve for t:
\n" ); document.write( "v=48t^2
\n" ); document.write( "20=48t^2
\n" ); document.write( "20/48 = t^2
\n" ); document.write( "\"sqrt%2820%2F48%29+=+t\"
\n" ); document.write( "0.645 seconds = t (hang time)
\n" ); document.write( "
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