document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=226303>Question 226303</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm trying to help my daughter with algerbra and I'm lost too!  Here is the problem:<BR>\n" );
document.write( "A group of ten 6 and 12 volt batteries are wired together.  The sum of their voltages is 84 volts.  How many of each type of battery are used?\r<BR>\n" );
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document.write( "I can get to the answer through process of elimination, but do not know how to set up the problem correctly.  Can you help?<BR>\n" );
document.write( "Mom </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #168556 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=168556\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if b=\"number of 6v\", then 10-b=\"number of 12v\"\r<BR>\n" );
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document.write( "6(b) + 12(10 - b) = 84\r<BR>\n" );
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document.write( "distributing ___ 6b + 120 - 12b = 84 ___ -6b = -36 ___ b = 6\r<BR>\n" );
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document.write( "six 6v and four 12v </SPAN>\n" );
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