document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=226275>Question 226275</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the price of a cellular telephone is based on peak and nonpeak service. kelsey used 45 peak and 50 nonpeak minutesand was charged $27.75. that same moth ,mitch used 70 peak minutes and 30 nonpeak minutes for a total charge of $36. what are the rates per minute for peak and nonpeak time?<BR>\n" );
document.write( "i got 45p+50n=27.75<BR>\n" );
document.write( "      70p+30n=36.00<BR>\n" );
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document.write( "were do i go from here <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #168547 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=168547\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> multiplying 1st eqn by -3/5 ___ -27p - 30n = -16.65\r<BR>\n" );
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document.write( "adding 2nd eqn ___ 43p = 19.35\r<BR>\n" );
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document.write( "dividing by 43 ___ p = .45\r<BR>\n" );
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document.write( "substituting ___ 70(.45) + 30n = 36.00 ___ 31.50 + 30n = 36.00 ___ 30n = 4.50 ___ n = .15 </SPAN>\n" );
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