document.write( "Question 226269: the second of two numbers is 4 times the first. their sum is 50. find the number\r
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document.write( "i dont understand the question at alllll. :( \n" );
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Algebra.Com's Answer #168539 by Abyssalanine(3)![]() ![]() ![]() You can put this solution on YOUR website! Two of the numbers are Number 1 : (N1), and Number 2 : (N2).\r \n" ); document.write( "\n" ); document.write( "Both numbers add up to equal 50.\r \n" ); document.write( "\n" ); document.write( "N1 + N2 = 50\r \n" ); document.write( "\n" ); document.write( "One is 4 times the other; for example I will use (N2).\r \n" ); document.write( "\n" ); document.write( "N2 = 4(N1)\r \n" ); document.write( "\n" ); document.write( "Substitute N2 in with 4(N1).\r \n" ); document.write( "\n" ); document.write( "N1 + 4N1 = 50\r \n" ); document.write( "\n" ); document.write( "5N1 = 50\r \n" ); document.write( "\n" ); document.write( "5N1/5 = N1 \n" ); document.write( "50/5 = 10\r \n" ); document.write( "\n" ); document.write( "N1 = 10\r \n" ); document.write( "\n" ); document.write( "Substitute N1 with 10.\r \n" ); document.write( "\n" ); document.write( "10 + N2 = 50\r \n" ); document.write( "\n" ); document.write( "10 - 10 = 0 \n" ); document.write( "50 - 10 = 40\r \n" ); document.write( "\n" ); document.write( "N2 = 40\r \n" ); document.write( "\n" ); document.write( "In the end, the two numbers are 10 and 40. \n" ); document.write( " |