document.write( "Question 226268: The sum of four consecutive odd integers is 216 . Find the four integers \n" ); document.write( "
Algebra.Com's Answer #168534 by drj(1380)\"\" \"About 
You can put this solution on YOUR website!
The sum of four consecutive odd integers is 216 . Find the four integers\r
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\n" ); document.write( "\n" ); document.write( "Step 1. Let n be the first odd integer.\r
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\n" ); document.write( "\n" ); document.write( "Step 2. Let n+2, n+4, and n+6 be the next three consecutive odd integers\r
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\n" ); document.write( "\n" ); document.write( "Step 3. Then, n+n+2+n+4+n+6=216 since the sum of the four consecutive odd integers is 216.\r
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\n" ); document.write( "\n" ); document.write( "Step 4. Solving the equation in Step 4 yields the following steps\r
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Solved by pluggable solver: EXPLAIN simplification of an expression
Your Result:

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\n" ); document.write( " YOUR ANSWER\n" ); document.write( "


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  • This is an equation! Solutions: n=51.
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  • Graphical form: Equation \"n%2Bn%2B2%2Bn%2B4%2Bn%2B6=216\" was fully solved.
  • Text form: n+n+2+n+4+n+6=216 simplifies to 0=0
  • Cartoon (animation) form: \"simplify_cartoon%28+n%2Bn%2B2%2Bn%2B4%2Bn%2B6=216+%29\"
    For tutors: simplify_cartoon( n+n+2+n+4+n+6=216 )
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  • If you have a website, here's a link to this solution.
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DETAILED EXPLANATION

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Look at \"n%2Bn%2Bhighlight_red%28+2+%29%2Bn%2Bhighlight_red%28+4+%29%2Bn%2Bhighlight_red%28+6+%29=216\".
Added fractions or integers together
It becomes \"n%2Bn%2Bhighlight_green%28+12+%29%2Bn%2Bn=216\".
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Look at \"n%2Bn%2Bhighlight_red%28+12+%29%2Bn%2Bn=216\".
Moved \"12\" to the right of expression
It becomes \"n%2Bn%2Bn%2Bn%2Bhighlight_green%28+12+%29=216\".
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Look at .
Eliminated similar terms \"highlight_red%28+n+%29\",\"highlight_red%28+n+%29\",\"highlight_red%28+n+%29\",\"highlight_red%28+n+%29\" replacing them with \"highlight_green%28+%281%2B1%2B1%2B1%29%2An+%29\"
It becomes \"highlight_green%28+%281%2B1%2B1%2B1%29%2An+%29%2B12=216\".
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Look at .
Added fractions or integers together
It becomes \"%28highlight_green%28+4+%29%29%2An%2B12=216\".
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Look at \"highlight_red%28+%28highlight_red%28+4+%29%29%2An+%29%2B12=216\".
Remove unneeded parentheses around factor \"highlight_red%28+4+%29\"
It becomes \"highlight_green%28+4+%29%2An%2B12=216\".
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Look at \"4%2An%2B12=highlight_red%28+216+%29\".
Moved these terms to the left \"highlight_green%28+-216+%29\"
It becomes \"4%2An%2B12-highlight_green%28+216+%29=0\".
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Look at \"4%2An%2Bhighlight_red%28+12+%29-highlight_red%28+216+%29=0\".
Added fractions or integers together
It becomes \"4%2An%2Bhighlight_green%28+-204+%29=0\".
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Look at \"4%2An%2Bhighlight_red%28+-204+%29=0\".
Removed extra sign in front of \"-204\"
It becomes \"4%2An-highlight_green%28+204+%29=0\".
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Look at \"highlight_red%28+4%2An-204+%29=0\".
Solved linear equation \"highlight_red%28+4%2An-204=0+%29\" equivalent to 4*n-204 =0
It becomes \"highlight_green%28+0+%29=0\".
Result: \"0=0\"
\n" ); document.write( "This is an equation! Solutions: n=51.

Universal Simplifier and Solver

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Done!

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\n" ); document.write( "\n" ); document.write( "With n=51, then n+2=53, n+4=55, and n+6=57. Also 51+53+55+57=216 as a check...\r
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\n" ); document.write( "\n" ); document.write( "Step 5. The four consecutive odd integers are 51, 53, 55, and 57\r
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\n" ); document.write( "\n" ); document.write( "I hope the above steps were helpful. \r
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\n" ); document.write( "\n" ); document.write( "For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.\r
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\n" ); document.write( "\n" ); document.write( "And good luck in your studies!\r
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\n" ); document.write( "\n" ); document.write( "Respectfully,
\n" ); document.write( "Dr J\r
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\n" ); document.write( "\n" ); document.write( "drjctu@gmail.com\r
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