document.write( "Question 226239: one phone company charges 16.95 per month and .05 per minute foe local calls. another charges 22.95 per month and .02 per minute for local calls. For what numbers of minutes of local calls per month is the cost the same? \n" ); document.write( "

Algebra.Com's Answer #168515 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"C\"$ = cost to use phone per month
\n" ); document.write( "Let $\"t\"$ = number of total minutes per month
\n" ); document.write( "1st phone company:
\n" ); document.write( " $\"C+=+1695+%2B+5t\"$ (in cents)
\n" ); document.write( "2nd phone company:
\n" ); document.write( " $\"C+=+2295+%2B+2t\"$
\n" ); document.write( "The costs are the same when:
\n" ); document.write( " $\"1695+%2B+5t+=+2295+%2B+2t\"$
\n" ); document.write( " $\"3t+=+600\"$
\n" ); document.write( " $\"t+=+200\"$
\n" ); document.write( "When local calls/mo = 200 min, the costs are the same
\n" ); document.write( "check:
\n" ); document.write( " $\"C+=+1695+%2B+5t\"$
\n" ); document.write( " $\"C+=+1695+%2B+5%2A200\"$
\n" ); document.write( " $\"C+=+1695+%2B+1000\"$
\n" ); document.write( " $\"C+=+2695\"$
\n" ); document.write( "and
\n" ); document.write( " $\"C+=+2295+%2B+2t\"$
\n" ); document.write( " $\"C+=+2295+%2B+2%2A200\"$
\n" ); document.write( " $\"C+=+2295+%2B+400\"$
\n" ); document.write( " $\"C+=+2695\"$
\n" ); document.write( "OK \n" ); document.write( "

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