document.write( "Question 30093: Lina Chen invested $24,000, part at 8% and the rest at 7.2%. How much did she invest at each rate if her income from the 8% investment is two thirds of the 7.2% investment? \n" ); document.write( "
Algebra.Com's Answer #16847 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! x = amount invested @ 8% \n" ); document.write( "(24000 - x) = amount invested @ 7.2% \n" ); document.write( "(.08)*x = 2/3(.072)(24000 - x) \n" ); document.write( "3*(.08x) = 2*(.072)(24000 - x) \n" ); document.write( ".24x = .144(24000 - x) \n" ); document.write( ".24x = 3456 - .144x \n" ); document.write( ".384x = 3456 \n" ); document.write( "x = 9000 \n" ); document.write( "(24000 - x) = 15000 \n" ); document.write( "check \n" ); document.write( "(.08)*9000 = 2/3(.072)(24000 - 9000) \n" ); document.write( "720 = 2/3(.072)(15000) \n" ); document.write( "720 = (.144)(5000) \n" ); document.write( "720 = 720 \n" ); document.write( " |