document.write( "Question 30093: Lina Chen invested $24,000, part at 8% and the rest at 7.2%. How much did she invest at each rate if her income from the 8% investment is two thirds of the 7.2% investment? \n" ); document.write( "
Algebra.Com's Answer #16847 by josmiceli(19441)\"\" \"About 
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x = amount invested @ 8%
\n" ); document.write( "(24000 - x) = amount invested @ 7.2%
\n" ); document.write( "(.08)*x = 2/3(.072)(24000 - x)
\n" ); document.write( "3*(.08x) = 2*(.072)(24000 - x)
\n" ); document.write( ".24x = .144(24000 - x)
\n" ); document.write( ".24x = 3456 - .144x
\n" ); document.write( ".384x = 3456
\n" ); document.write( "x = 9000
\n" ); document.write( "(24000 - x) = 15000
\n" ); document.write( "check
\n" ); document.write( "(.08)*9000 = 2/3(.072)(24000 - 9000)
\n" ); document.write( "720 = 2/3(.072)(15000)
\n" ); document.write( "720 = (.144)(5000)
\n" ); document.write( "720 = 720
\n" ); document.write( "
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