document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=226005>Question 226005</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Torque left home on his bicycle at 9:00 A.M., traveling at an average rate of 12 mph. At noon, Torque's brother set out after him on a motorcycle, following the same route, averaging 39 mph. How long had Torque been riding when his brother caught up? \r<BR>\n" );
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document.write( "Will you help me set up the equation for this? i don't quite understand travel questions and I have a test in two days. \r<BR>\n" );
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document.write( "Thanks,  \r<BR>\n" );
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document.write( "Emily M.<BR>\n" );
document.write( "Ohio </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #168436 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=168436\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Torque left home on his bicycle at 9:00 A.M., traveling at an average rate of 12 mph.<BR>\n" );
document.write( " At noon, Torque's brother set out after him on a motorcycle, following the same route, averaging 39 mph.<BR>\n" );
document.write( " How long had Torque been riding when his brother caught up?<BR>\n" );
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document.write( "Let t = time Torque had been riding<BR>\n" );
document.write( "then the brother starts, 3hrs later, therefore<BR>\n" );
document.write( "(t-3) = travel time of the brother<BR>\n" );
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document.write( "A good fact to remember in these \"catch up\" problems, is when this occurs,<BR>\n" );
document.write( "they both will have traveled the same distance<BR>\n" );
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document.write( "write a distance equation from this fact; (dist = speed * time)<BR>\n" );
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document.write( "bro dist = T's dist<BR>\n" );
document.write( "39(t - 3) = 12t<BR>\n" );
document.write( "39t - 117 = 12t<BR>\n" );
document.write( "39t - 12t = +117<BR>\n" );
document.write( "27t = 117<BR>\n" );
document.write( "t = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=117%2F27 ALIGN=MIDDLE  ALT=\"117%2F27\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "t = 4<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F3 ALIGN=MIDDLE  ALT=\"1%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" > hrs (4 hr 20 min) is the riding time of T<BR>\n" );
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document.write( "Check the solution by finding the dist traveled by each<BR>\n" );
document.write( "(bro traveled 4.33 - 3 = 1.33 hr)<BR>\n" );
document.write( "4.33 * 12 ~ 52 mi<BR>\n" );
document.write( "1.33 * 39 ~ 52 mi </SPAN>\n" );
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