document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=30107>Question 30107</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve by elemination method: <BR>\n" );
document.write( "5/2x+5/3y=25\r<BR>\n" );
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document.write( "1/4x+1/3y=3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #16843 by </B><A HREF=/tutors/aboutme.mpl?userid=Fermat><B>Fermat(136)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Fermat><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Fermat><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=16843\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (5/2)x + (5/3)y = 25<BR>\n" );
document.write( "(1/4)x + (1/3)y = 3<BR>\n" );
document.write( "To simplify some of the working, multiply the 1st eqn by 6 (LCM of 2 and 3) and multiply the 2nd eqn by 12 (LCM of 4 and 3) to give<BR>\n" );
document.write( "15x + 10y = 150<BR>\n" );
document.write( "3x + 4y = 36<BR>\n" );
document.write( "multiply the 2nd eqn by 5,<BR>\n" );
document.write( "15x + 10y = 150<BR>\n" );
document.write( "15x + 20y = 180<BR>\n" );
document.write( "subtract the 1st eqn from the 2nd, to eliminate the x-variable giving,<BR>\n" );
document.write( "10y = 30<BR>\n" );
document.write( "y = 3<BR>\n" );
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document.write( "now substitute for y = 3 into the eqn. 3x + 4y = 36<BR>\n" );
document.write( "3x + 12 = 36<BR>\n" );
document.write( "3x = 24<BR>\n" );
document.write( "x = 8<BR>\n" );
document.write( "===== </SPAN>\n" );
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