document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=30106>Question 30106</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you seperate 116 ito two parts,where one of which shall be 3 times the other?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #16842 by </B><A HREF=/tutors/aboutme.mpl?userid=Fermat><B>Fermat(136)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Fermat><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Fermat><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=16842\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let one part be x<BR>\n" );
document.write( "let the other part be y<BR>\n" );
document.write( "then x = 3y, say<BR>\n" );
document.write( "Also,<BR>\n" );
document.write( "116 = x + y<BR>\n" );
document.write( "substitute for x = 3y into the above eqn<BR>\n" );
document.write( "116 = 3y + y<BR>\n" );
document.write( "116 = 4y<BR>\n" );
document.write( "divide both sides by 4,<BR>\n" );
document.write( "29 = y<BR>\n" );
document.write( "y = 29<BR>\n" );
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document.write( "x = 87 (87 = 3*29)<BR>\n" );
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document.write( "</TD></TR></TABLE>\n" );