document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=225949>Question 225949</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Could you help me with this problem please?\r<BR>\n" );
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document.write( "Find the area of a triangle formed by the x-axis, the line y=-6x+60, and the line 3x-4y=-24. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #168417 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=168417\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the area of a triangle formed by the x-axis, the line y=-6x+60, and the line 3x-4y=-24.<BR>\n" );
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document.write( "Find where the 2 lines intersect.<BR>\n" );
document.write( "y = -6x+60<BR>\n" );
document.write( "3x-4y = -24<BR>\n" );
document.write( "Sub for y in 2nd eqn<BR>\n" );
document.write( "3x - 4(-6x+60) = -24<BR>\n" );
document.write( "3x + 24x-240 = -24<BR>\n" );
document.write( "27x = 216<BR>\n" );
document.write( "x = 8<BR>\n" );
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document.write( "y = -6x+60 = 12<BR>\n" );
document.write( "--> (8,12)<BR>\n" );
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document.write( "Find the x-intercepts of the 2 lines by setting y=0.<BR>\n" );
document.write( "y = -6x+60<BR>\n" );
document.write( "0 = -6x+60<BR>\n" );
document.write( "x = 10<BR>\n" );
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document.write( "3x-4y = -24<BR>\n" );
document.write( "3x = -24<BR>\n" );
document.write( "x = -8<BR>\n" );
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document.write( "The base of the triangle is from x = -8 to x = 10, = 18 units.<BR>\n" );
document.write( "The height is the y value of the intersection, = 12<BR>\n" );
document.write( "Area = b*h/2 = 18*12/2<BR>\n" );
document.write( "Area = 108 sq units. </SPAN>\n" );
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