document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=225950>Question 225950</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Express that area A of an equilateral triangle as a function of the perimeter P.  My classmates and I have been trying to figure this out for two hours.  The work is messy and complicated or I would have put it on here. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #168404 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=168404\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if the perimeter is P, then one side is P/3\r<BR>\n" );
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document.write( "because half of the equilateral is a 30-60-90 right triangle; that makes the base P/3 and the height (P&#8730;3)/6\r<BR>\n" );
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document.write( "A = 1/2 * b * h = 1/2 * P/3 * (P&#8730;3)/6 = (P^2 * &#8730;3) / 36 </SPAN>\n" );
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