document.write( "Question 225964: Point (1, –2) , m = –5. \n" ); document.write( "
Algebra.Com's Answer #168402 by drj(1380)\"\" \"About 
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Point (1, –2) , m = –5.\r
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\n" ); document.write( "\n" ); document.write( "I assume you want to write the slope intercept form of the equation of the line through the given point (1,-2) with the given slope m=-5.\r
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\n" ); document.write( "\n" ); document.write( "Step 1. The slope-intercept form is given as y=mx+b where m is the slope and b is the y-intercept when x=0 or at point (0,b).\r
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\n" ); document.write( "\n" ); document.write( "Step 2. Now we have to find the line with slope m=-5 going through point (1,-2).\r
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\n" ); document.write( "\n" ); document.write( "Step 3. Given two points (x1,y1) and (x2,y2), then the slope m is given as\r
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\n" ); document.write( "\n" ); document.write( "\"m=%28y2-y1%29%2F%28x2-x1%29\"\r
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\n" ); document.write( "\n" ); document.write( "Step 4. Let (x1,y1)=(1,-2) or x1=1 and y1=-2. Let other point be (x2,y2)=(x,y) or x2=x and y2=y.\r
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\n" ); document.write( "\n" ); document.write( "Step 5. Now we're given \"m=-5\". Substituting above values and variables in the slope equation m yields the following steps:\r
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\n" ); document.write( "\n" ); document.write( "\"m=%28y2-y1%29%2F%28x2-x1%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"-5=%28y-%28-2%29%29%2F%28x-1%29=%28y%2B2%29%2F%28x-1%29\"\r
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\n" ); document.write( "\n" ); document.write( "Step 6. Multiply x-1 to both sides to get rid of denominator on right side of equation.\r
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\n" ); document.write( "\n" ); document.write( "\"-5%28x-1%29=y%2B2\" \r
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\n" ); document.write( "\n" ); document.write( "\"-5x%2B5=y%2B2\" \r
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\n" ); document.write( "\n" ); document.write( "Step 7. Add -2 to both sides of the equation\r
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\n" ); document.write( "\n" ); document.write( "\"-5x%2B5%2B%28-2%29=y%2B2%2B%28-2%29\" \r
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\n" ); document.write( "\n" ); document.write( "\"-5x%2B3=y\" \r
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\n" ); document.write( "\n" ); document.write( "Step 7. ANSWER: The equation in slope-intercept form is \"y=-5x%2B3\" where the slope m=7 and the y-intercept b=-5.\r
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\n" ); document.write( "\n" ); document.write( "Note: the above equation can be rewritten in standard form as\r
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\n" ); document.write( "\n" ); document.write( "\"5x%2By=%2B3\"\r
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\n" ); document.write( "\n" ); document.write( "And the graph is shown below which is consistent with the above steps.\r
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Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc
Equation \"5+x+%2B+1+y+=+3\" describes a sloping line. For any
\n" ); document.write( " equation ax+by+c = 0, slope is \"-a%2Fb+=+-5%2F1\".
  • X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. 3/5 = 0.6.
  • Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is 3/1 = 3.
  • Slope is -5/1 = -5.
  • Equation in slope-intercept form: y=-5*x+3.
\"graph%28+500%2C+500%2C+0.6-8%2C+0.6%2B8%2C+3-8%2C+3%2B8%2C+-5%2Ax%2B3+%29+\"\n" ); document.write( "

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\n" ); document.write( "\n" ); document.write( "I hope the above steps and explanation were helpful.\r
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\n" ); document.write( "\n" ); document.write( "For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.\r
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\n" ); document.write( "\n" ); document.write( "And good luck in your studies!\r
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\n" ); document.write( "\n" ); document.write( "Respectfully,
\n" ); document.write( "Dr J\r
\n" ); document.write( "\n" ); document.write( "http://www.FreedomUniversity.TV
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