document.write( "Question 225879: How do i solve this?
\n" ); document.write( "I have tried many different ways, asked tons of people. And no one can figure it out.
\n" ); document.write( "Find the values for a and k in the function {{ y=ax^2+k}} that contains the points (2,0) and (4,-6).
\n" ); document.write( "Thank you i would really appreciate it.
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Algebra.Com's Answer #168395 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"y=ax%5E2%2Bk\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"0=a%282%29%5E2%2Bk\" Plug in \"x=2\" and \"y=0\" from the given point (2,0)\r
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\n" ); document.write( "\n" ); document.write( "\"0=4a%2Bk\" Square 2 to get 4.\r
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\n" ); document.write( "\n" ); document.write( "\"-4a=k\" Subtract 4a from both sides.\r
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\n" ); document.write( "\n" ); document.write( "So \"k=-4a\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=ax%5E2%2Bk\" Go back to the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"-6=a%284%29%5E2%2Bk\" Plug in \"x=4\" and \"y=-6\" from the given point (4,-6)\r
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\n" ); document.write( "\n" ); document.write( "\"-6=16a%2Bk\" Square 4 to get 16.\r
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\n" ); document.write( "\n" ); document.write( "\"-6=16a-4a\" Plug in \"k=-4a\"\r
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\n" ); document.write( "\n" ); document.write( "From here, solve for 'a'. Once you have the value of 'a', plug it into \"k=-4a\" to find 'k'.
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