document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=30100>Question 30100</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the slope if it exists of the line containing the points (-6,1/2) and (-9,1/2) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #16839 by </B><A HREF=/tutors/aboutme.mpl?userid=Fermat><B>Fermat(136)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Fermat><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Fermat><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=16839\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If you have two points (x1,y1) and (x2,y2), then the slope of the line between these two points is given by\r<BR>\n" );
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document.write( "m = (y1-y2)/(x1-x2)<BR>\n" );
document.write( "Using the points given,(-6,1/2) and (-9,1/2)<BR>\n" );
document.write( "m = (1/2 - 1/2)/(-6 + 9)<BR>\n" );
document.write( "m = 0/3<BR>\n" );
document.write( "m = 0<BR>\n" );
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document.write( "Since the slope is zero, then the line is a horizontal line which cuts the y-axis at y = 1/2.<BR>\n" );
document.write( "In fact, y=1/2 is the name of this line.<BR>\n" );
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