document.write( "Question 225693: How can $28,000 be invested, part at 4% annual simple interest and the remainder at 10% annual simple interest, so that the interest earned by the two accounts is equal at the end of the year \n" ); document.write( "

Algebra.Com's Answer #168318 by checkley77(12844) $\"\"$ $\"About$

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.10X=.04(10,000-X)
\n" ); document.write( ".10X=400-.04X
\n" ); document.write( ".14X=400
\n" ); document.write( "X=400/.14
\n" ); document.write( "X=2,857 INVESTED @ 10%.
\n" ); document.write( "10,000-2,857=7,143 INVESTED @ 4%.
\n" ); document.write( ".10*2,857=.04*7,143
\n" ); document.write( "285.7=285.7
\n" ); document.write( " \n" ); document.write( "

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