document.write( "Question 225444: A six passenger plane cruises at 180mph in calm air. If the plane flys 7 miles with the wind in the same amount of time as it flys 5 miles against the wind, what is the wind speed. \n" ); document.write( "
Algebra.Com's Answer #168282 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! D=RT OR T=D/R \n" ); document.write( "T=7/(180-W) \n" ); document.write( "T=5/(180+W) \n" ); document.write( "SET THE 2 TIME EQUATIONS EQUAL & SOLVE FOR THE WIND SPED. \n" ); document.write( "7/(180-W)=5/(180+W) \n" ); document.write( "5(180-W)=7(180+W) \n" ); document.write( "900-5W=1,260+7W \n" ); document.write( "-7W-5W=1,260-900 \n" ); document.write( "-12W=360 \n" ); document.write( "W=360/-12 \n" ); document.write( "W=-30 MPH IS THE WIND SPEED. \n" ); document.write( "PROOF: \n" ); document.write( "7/(180-(-30))=5(180/(180+(-30)) \n" ); document.write( "7/(180+30)=5(180-30) \n" ); document.write( "7/210=5/150 \n" ); document.write( "5*210=7*150 \n" ); document.write( "1,050=1,050 \n" ); document.write( " |