document.write( "Question 29996: Could you please help me with this problem \r
\n" ); document.write( "\n" ); document.write( "Solve for x \r
\n" ); document.write( "\n" ); document.write( "\"10+over+x%5E2-2x+%2B+4+over+x\" = 5 over x-2
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Algebra.Com's Answer #16819 by sdmmadam@yahoo.com(530)\"\" \"About 
You can put this solution on YOUR website!
10 over x^2-2x + 4 over x = 5 over x-2
\n" ); document.write( "10/(x^2-2x) + 4/x = 5/(x-2) ----(1)
\n" ); document.write( "10/x(x-2) + 4/x = 5/(x-2)
\n" ); document.write( "Multiplying by x(x-2) through out
\n" ); document.write( "10+4(x-2)=5x ----(2)
\n" ); document.write( "10+4x-8 = 5x
\n" ); document.write( "(10-8) = 5x-4x (grouping like terms,changing sign while changing side)
\n" ); document.write( "2 = x
\n" ); document.write( "That is x = 2
\n" ); document.write( "Verification:Putting x= 2 in (1) we arrive at division by zero which is not defined as 0 does not have multiplicative inverse
\n" ); document.write( "The value x = 2 holds in the version (2) of the problem where there is no division by the factor (x-2)
\n" ); document.write( "Note:Why 0 does not have multiplicative inverse?
\n" ); document.write( "Any real number a NOT ZERO is said to have multiplicative iverse b NOT ZERO only when (b)X(a) = 1 = (a)X(b)
\n" ); document.write( "We call this b the multiplicative inverse of a and write b as b = (1/a)
\n" ); document.write( "Why should a (or for that matter) be NOT ZERO?
\n" ); document.write( "Supposing a= 0
\n" ); document.write( "and if it should have multiplicative inverse then we should find that something called inverse of zer0 so that
\n" ); document.write( "(0)X(something)=1 =(that same something)X(0)
\n" ); document.write( "But then we know that (0) X (anything ) is always zero and NOT 1
\n" ); document.write( "Hence 0 does not have multiplicative inverse.
\n" ); document.write( "That is the multiplicative inverse of 0
\n" ); document.write( "namely (1/0)does not exist
\n" ); document.write( "That is division by 0 is not defined.
\n" ); document.write( "Got it!
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