document.write( "Question 225401: Nancy Johnson invested $18,000. Part of it was invested at 3% annual simple interest, and the rest was invested at 4%. Her interest income for the first year was $650. How much did she invest at each rate? \r
\n" ); document.write( "\n" ); document.write( "This is what I tried: 3x + 4y = 650;
\n" ); document.write( " y=18x
\n" ); document.write( " 3(18y) + 4y = 650
\n" ); document.write( " 54y + 4y = 650 = 58y =650, y=11.206896
\n" ); document.write( "I got lost from there because when that would make X something not nice. Please help me?
\n" ); document.write( "

Algebra.Com's Answer #168184 by rfer(16322)\"\" \"About 
You can put this solution on YOUR website!
.03x+.04(18000-x)=650
\n" ); document.write( ".03x+720-.04x=650
\n" ); document.write( "-.01x=-70
\n" ); document.write( "x=$7000 in 3%
\n" ); document.write( "18000-x=$11000 in 4%
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