document.write( "Question 225337: THe sume of two numbers is 90. If 20 is added 3 times the smaller number, the result exceeds twice the larger number by 50. Let A represent the smaller number and let B represent the larger number.\r
\n" ); document.write( "\n" ); document.write( "a+b=90
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Algebra.Com's Answer #168164 by LtAurora(115)\"\" \"About 
You can put this solution on YOUR website!
Our given equations are:
\n" ); document.write( "\"A%2BB=90\"
\n" ); document.write( "\"20%2B3A=2B%2B50\"
\n" ); document.write( "Solve the first one for a variable:
\n" ); document.write( "\"A=90-B\"
\n" ); document.write( "Plug this into the second equation:
\n" ); document.write( "\"20%2B3%2890-B%29=2B%2B50\"
\n" ); document.write( "Distribute the 3:
\n" ); document.write( "\"20%2B270-3B=2B%2B50\"
\n" ); document.write( "Combine like terms:
\n" ); document.write( "\"290-3B=2B%2B50\"
\n" ); document.write( "Move the -3B to the other side by adding it:
\n" ); document.write( "\"290=5B%2B50\"
\n" ); document.write( "Move the 50 over by subtracting it:
\n" ); document.write( "(((240=5B}}}
\n" ); document.write( "Divide both sides by 5:
\n" ); document.write( "\"B=48\"
\n" ); document.write( "Plug this back into our equation:
\n" ); document.write( "\"A=90-48\"
\n" ); document.write( "\"A=42\"
\n" ); document.write( "So, \"A=42\" and \"B=48\".
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