document.write( "Question 225322: Can anyone explain this to me, I am stumped and can't figure it out. Please I need help..\r
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document.write( "1. 4X2 - 4X+3= 0
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document.write( "2. X2+12X-64=0 \r
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document.write( "a. move the constant term to the right side of the equation
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document.write( "b. multiply each term in the equation by four times the cofficient of the x2 term
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document.write( "c. square the coefficient of the original x term and add it to both sides of the equation
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document.write( "d. take the square root of both sides
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document.write( "e. set the left side of the equation equal to the positive square root of the number on the right side and slove for x
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document.write( "f. set the left side of the equation equal to the negative square root of the number on the right side of the equation and slove for x \n" );
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Algebra.Com's Answer #168155 by jsmallt9(3758)![]() ![]() ![]() You can put this solution on YOUR website! First let me say that this is an odd (and incomplete) way of completing the square. Anyway, let's proceed... \n" ); document.write( " \n" ); document.write( "a. move the constant term to the right side of the equation \n" ); document.write( " \n" ); document.write( "b. multiply each term in the equation by four times the cofficient of the x2 term \n" ); document.write( "4*4 = 16 so: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "c. square the coefficient of the original x term and add it to both sides of the equation \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "A step that is missing here is to write the left side as a perfect square. After the steps so far the left side should fit one of the following patterns: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "d. take the square root of both sides \n" ); document.write( "At this point, with this equation, we have a problem. The left side is a perfect square. The right side is a negative number. Unless we are working with complex numbers, there are no perfect squares that are negative. So this equation has no solutions. \n" ); document.write( " \n" ); document.write( "a. move the constant term to the right side of the equation \n" ); document.write( " \n" ); document.write( "b. multiply each term in the equation by four times the cofficient of the x2 term \n" ); document.write( "4*1 = 4 so: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "c. square the coefficient of the original x term and add it to both sides of the equation \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Missing step: Rewrite as a perfect square. The left side fits the first perfect square pattern (see above) with \"2x\" as \"a\" and \"12\" as \"b\": \n" ); document.write( " \n" ); document.write( "d. take the square root of both sides \n" ); document.write( " \n" ); document.write( "e. set the left side of the equation equal to the positive square root of the number on the right side and slove for x \n" ); document.write( "Since \n" ); document.write( "2x + 12 = 20 \n" ); document.write( "2x = 8 \n" ); document.write( "x = 4 \n" ); document.write( "f. set the left side of the equation equal to the negative square root of the number on the right side of the equation and slove for x \n" ); document.write( "2x + 12 = -20 \n" ); document.write( "2x = -32 \n" ); document.write( "x = -16 \n" ); document.write( " |