document.write( "Question 225239: factor by grouping:
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Algebra.Com's Answer #168135 by drj(1380)\"\" \"About 
You can put this solution on YOUR website!
Factor by grouping:\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B2xy%2B3x%2B6y\"\r
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\n" ); document.write( "\n" ); document.write( "Step 1. Factor out x in the first two terms and factor out 3 in the last two terms:\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B2xy%2B3x%2B6y=x%28x%2B2y%29%2B3%28x%2B2y%29\"\r
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\n" ); document.write( "\n" ); document.write( "Step 2. The factor \"x%2B2y\" is common to both groups in parenthesis, so factor that out.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B2xy%2B3x%2B6y=%28x%2B2y%29%28x%2B3%29\"\r
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\n" ); document.write( "\n" ); document.write( "Step 3. ANSWER: \"x%5E2%2B2xy%2B3x%2B6y=%28x%2B2y%29%28x%2B3%29\"\r
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\n" ); document.write( "\n" ); document.write( "I hope the above steps were helpful. \r
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\n" ); document.write( "\n" ); document.write( "For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.\r
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\n" ); document.write( "\n" ); document.write( "And good luck in your studies!\r
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\n" ); document.write( "\n" ); document.write( "Respectfully,
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\n" ); document.write( "\n" ); document.write( "drjctu@gmail.com\r
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