document.write( "Question 225271: An automobile radiator contains 16 liters of antifreeze and water. This mixture is 30% antifreeze. How much of this mixture should be drained and replaced with pure antifreeze so that there will be 50% antifreeze? \n" ); document.write( "
Algebra.Com's Answer #168130 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! Let \n" ); document.write( "and replaced with pure antifreeze. \n" ); document.write( "In words: \n" ); document.write( "(liters of antifreeze I end up with)/(final total liters in radiator) = 50% \n" ); document.write( "Notice that I start with 16 liters in the radiator \n" ); document.write( "and I end up with 16 liters in the radiator, so I can write \n" ); document.write( "(liters of antifreeze I end up with)/16 = 50% \n" ); document.write( "16 liters of 30% antifreeze has \n" ); document.write( "I drain out \n" ); document.write( "antifreeze \n" ); document.write( "So far, I've got \n" ); document.write( "Now I pour in \n" ); document.write( "I end up with \n" ); document.write( "My equation is then \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "4.571 liters need to be drained out and \n" ); document.write( "replaced with pure antifreeze \n" ); document.write( "check answer \n" ); document.write( "If I replace \n" ); document.write( "to 30% in the whole radiator \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "OK \n" ); document.write( " \n" ); document.write( " |