document.write( "Question 225271: An automobile radiator contains 16 liters of antifreeze and water. This mixture is 30% antifreeze. How much of this mixture should be drained and replaced with pure antifreeze so that there will be 50% antifreeze? \n" ); document.write( "
Algebra.Com's Answer #168130 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"x\" = liters of mixture to be drained
\n" ); document.write( "and replaced with pure antifreeze.
\n" ); document.write( "In words:
\n" ); document.write( "(liters of antifreeze I end up with)/(final total liters in radiator) = 50%
\n" ); document.write( "Notice that I start with 16 liters in the radiator
\n" ); document.write( "and I end up with 16 liters in the radiator, so I can write
\n" ); document.write( "(liters of antifreeze I end up with)/16 = 50%
\n" ); document.write( "16 liters of 30% antifreeze has \".3%2A16+=+4.8\" liters antifreeze
\n" ); document.write( "I drain out \"x\" liters, and in doing so, I remove .3x liters
\n" ); document.write( "antifreeze
\n" ); document.write( "So far, I've got \"4.8+-+.3x\" liters antifreeze in radiator
\n" ); document.write( "Now I pour in \"x\" liters of antifreeze
\n" ); document.write( "I end up with \"4.8+-+.3x+%2B+x\" liters antifreeze
\n" ); document.write( "My equation is then
\n" ); document.write( "\"%284.8+%2B+.7x%29%2F16+=+.5\"
\n" ); document.write( "\"4.8+%2B+.7x+=+8\"
\n" ); document.write( "\".7x+=+3.2\"
\n" ); document.write( "\"x+=+4.571\" liters
\n" ); document.write( "4.571 liters need to be drained out and
\n" ); document.write( "replaced with pure antifreeze
\n" ); document.write( "check answer
\n" ); document.write( "If I replace \"x\" with a 30% mixture again, I'll be back
\n" ); document.write( "to 30% in the whole radiator
\n" ); document.write( "\".3%2A4.571+=+1.371\" liters antifreeze
\n" ); document.write( "\"16+-+4.571+=+11.429\"
\n" ); document.write( "\".3%2A11.429+=+3.429\" liters antifreeze in rest of radiator
\n" ); document.write( "\"%281.371+%2B+3.429%29%2F16+=+.3\"
\n" ); document.write( "\"4.8%2F16+=+.3\"
\n" ); document.write( "\"4.8+=+4.8\"
\n" ); document.write( "OK
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