document.write( "Question 225263: If two numbers are both increased by 10, their product is increased by 550. If twice the smaller number exceeds the larger by 15, find the numbers. \n" ); document.write( "
Algebra.Com's Answer #168126 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Two numbers, x & y \n" ); document.write( ": \n" ); document.write( "write an equation for each statement: \n" ); document.write( ": \n" ); document.write( "If two numbers are both increased by 10, their product is increased by 550. \n" ); document.write( "New no. product - original product = 550 \n" ); document.write( "(x+10)*(y+10) - xy = 550 \n" ); document.write( "FOIL \n" ); document.write( "xy + 10x + 10y + 100 - xy = 550 \n" ); document.write( "xy's cancel \n" ); document.write( "10x + 10y + 100 = 550 \n" ); document.write( "10x + 10y = 550 - 100 \n" ); document.write( "10x + 10y = 450 \n" ); document.write( "Simplify, divide by 10 \n" ); document.write( "x + y = 45 \n" ); document.write( ": \n" ); document.write( " If twice the smaller number exceeds the larger by 15, \n" ); document.write( "x = 2y - 15 \n" ); document.write( ": \n" ); document.write( " find the numbers. \n" ); document.write( "Replace x in the 1st equation with (2y-15) \n" ); document.write( "(2y-15) + y = 45 \n" ); document.write( "2y + y = 45 + 15 \n" ); document.write( "3y = 60 \n" ); document.write( "y = \n" ); document.write( "y = 20 \n" ); document.write( ": \n" ); document.write( "Find x: \n" ); document.write( "x = 2(20) - 15 \n" ); document.write( "x = 25 \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "See if that works in the 1st statement \n" ); document.write( "35*30 - 25*20 = \n" ); document.write( "1050 = 500 = 550 \n" ); document.write( " |