document.write( "Question 225247: Solve this quadratic equation using the Difference of Two Squares rule:
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\n" ); document.write( "\n" ); document.write( "Solve this quadratic equation using the \"multiply to give, add to give\" rule:
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Algebra.Com's Answer #168124 by Edwin McCravy(20056) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"8x%5E2-2=0\"$
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document.write( "Divide every term by 2\r\n" );
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document.write( "2x - 1 = 0      2x + 1 = 0\r\n" );
document.write( "    2x = 1          2x = -1\r\n" );
document.write( "     x =           x = \r\n" );
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document.write( "Multiply  by , get \r\n" );
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document.write( "Think of two numbers that multiply to \r\n" );
document.write( "give you  and add to give you .\r\n" );
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document.write( "Answer:  and \r\n" );
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document.write( "So use those numbers  and \r\n" );
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document.write( "to write the middle term  as \r\n" );
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document.write( "So\r\n" );
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document.write( "now becomes:\r\n" );
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document.write( "Now out of the first two terms on the left \r\n" );
document.write( "factor out \r\n" );
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document.write( "Out of the last two terms on the left \r\n" );
document.write( "factor out \r\n" );
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document.write( "Notice that  occurs in\r\n" );
document.write( "both terms on the left:\r\n" );
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document.write( "So factor out \r\n" );
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document.write( " x - 3 = 0      3x + 4 = 0\r\n" );
document.write( "     x = 3          3x = -4\r\n" );
document.write( "                     x =\r\n" );
document.write( "Edwin

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