document.write( "Question 225110: One number is 2 more than 5 times another. Their product is 3. Find the numbers. \n" ); document.write( "
Algebra.Com's Answer #168115 by LtAurora(115)\"\" \"About 
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The following relatiosn can be set up from the given information:
\n" ); document.write( "\"A=5B%2B2\"
\n" ); document.write( "\"AB=3\"
\n" ); document.write( "We can plug the first equation into the second:
\n" ); document.write( "\"%285B%2B2%29B=3\"
\n" ); document.write( "Distribute the B:
\n" ); document.write( "\"5B%5E2%2B2B=3\"
\n" ); document.write( "Move the 3 to the other side
\n" ); document.write( "\"5B%5E2%2B2B-3=0\"
\n" ); document.write( "This factors down to:
\n" ); document.write( "\"%285B-3%29%28B%2B1%29=0\"
\n" ); document.write( "Set these each equal to zero and solve:
\n" ); document.write( "\"5B-3=0\", \"B%2B1=0\"
\n" ); document.write( "\"5B=3\", \"B=-1\"
\n" ); document.write( "\"B=3%2F5\"
\n" ); document.write( "So, we have two possible answers, \"B=3%2F5\", \"B=-1\".
\n" ); document.write( "Plug this back into the first equation:
\n" ); document.write( "\"A=5%283%2F5%29%2B2\"
\n" ); document.write( "\"A=5\"
\n" ); document.write( "and
\n" ); document.write( "\"A=5%28-1%29%2B2\"
\n" ); document.write( "\"A=-3\"\r
\n" ); document.write( "\n" ); document.write( "Thus, the sets of equations are: \"A=5\", \"B=3%2F5\" AND \"A=-3\", \"B=-1\".
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