document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=225184>Question 225184</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Ben is making wooden toys for the next arts and crafts sale. Each toy cost Ben $1.80 to make. if he sells the toys for $3.00 each, how many will he have to sell to make a profit of exactly $36.00? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #168105 by </B><A HREF=/tutors/aboutme.mpl?userid=LtAurora><B>LtAurora(115)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=LtAurora><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=LtAurora><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=168105\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> THe equation we need to set up is:<BR>\n" );
document.write( "3x-1.8x=36<BR>\n" );
document.write( "Combine like terms:<BR>\n" );
document.write( "1.2x=36<BR>\n" );
document.write( "Divide both sides by 1.2:<BR>\n" );
document.write( "x=30<BR>\n" );
document.write( "So, he needs to sell 30 toys before he makes $36.00. I hope it doesn't take him long to make these things, because that seems to be a pretty awful profit. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );