document.write( "Question 222313: two angles of a triangle have the same measure and the third angle is 30 degrees greater than the measure of the other two. find the measure of each angle \n" ); document.write( "
Algebra.Com's Answer #168104 by LtAurora(115)\"\" \"About 
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All the angles of a triangle add up to 180 degrees.
\n" ); document.write( "Since two of the angles are the same, we can write:
\n" ); document.write( "\"2A%2BB=180\"
\n" ); document.write( "Where 2A accounts for the two angles that are the same.
\n" ); document.write( "We are given the relation:
\n" ); document.write( "\"B=A%2B30\"
\n" ); document.write( "We can plug this into our first equation:
\n" ); document.write( "\"2A%2BA%2B30=180\"
\n" ); document.write( "Combine like terms and move the 30 to the other side:
\n" ); document.write( "\"3A=150\"
\n" ); document.write( "Divide both sides by 3:
\n" ); document.write( "\"A=50\"
\n" ); document.write( "We can solve for B by plugging A back into our relation:
\n" ); document.write( "\"B=50%2B30\"
\n" ); document.write( "\"B=80\"
\n" ); document.write( "To check: \"80%2B50%2B50=180\", so we are correct.
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