document.write( "Question 225216: Advance tickets to a show cost 20 ,and same-day tickets cost 30. The total number of tickets sold was 60 for total receipts of 1600. How many tickets of each type were sold.\r
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Algebra.Com's Answer #168102 by LtAurora(115)\"\" \"About 
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From the given information we can say:
\n" ); document.write( "\"A%2BS=60\"
\n" ); document.write( "\"20A%2B30S=1600\"
\n" ); document.write( "Where A is the advance ticket and S is the same-day ticket.
\n" ); document.write( "Solve the first equation for one of the variables:
\n" ); document.write( "\"A=60-S\"
\n" ); document.write( "Then plug this into the second equation:
\n" ); document.write( "\"20%2860-S%29%2B30S=1600\"
\n" ); document.write( "Distribute the 20:
\n" ); document.write( "\"1200-20S%2B30S=1600\"
\n" ); document.write( "Move the 1200 to the other side and combine the S terms:
\n" ); document.write( "\"10S=400\"
\n" ); document.write( "Divide both sides by 10:
\n" ); document.write( "\"S=40\"
\n" ); document.write( "Plug this back into our first equation:
\n" ); document.write( "\"A=60-40=20\"
\n" ); document.write( "So, 40 same-day tickets were sold and 20 advance tickets.
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