document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=225108>Question 225108</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The hypotenuse of a right triangle is 5 inches. The lengths of the two legs are given by two consecutive integers. Find the lengths of the two legs. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #168055 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=168055\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the two legs be x and x+1, then from the Pythagorean theorem, we have:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2B%28x%2B1%29%5E2+=+5%5E2 ALIGN=MIDDLE  ALT=\"x%5E2%2B%28x%2B1%29%5E2+=+5%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2B%28x%5E2%2B2x%2B1%29+=+25 ALIGN=MIDDLE  ALT=\"x%5E2%2B%28x%5E2%2B2x%2B1%29+=+25\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x%5E2%2B2x%2B1+=+25 ALIGN=MIDDLE  ALT=\"2x%5E2%2B2x%2B1+=+25\"   DISABLED_style= \"max-width:90%; height:auto;\" > Subtract 25 from both sides.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x%5E2%2B2x-24+=+0 ALIGN=MIDDLE  ALT=\"2x%5E2%2B2x-24+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" > Factor out a 2.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%28x%5E2%2Bx-12%29+=+0 ALIGN=MIDDLE  ALT=\"2%28x%5E2%2Bx-12%29+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" > so...<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2Bx-12+=+0 ALIGN=MIDDLE  ALT=\"x%5E2%2Bx-12+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" > Factor this quadratic equation.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x%2B4%29%28x-3%29+=+0 ALIGN=MIDDLE  ALT=\"%28x%2B4%29%28x-3%29+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" > and...<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+-4 ALIGN=MIDDLE  ALT=\"x+=+-4\"   DISABLED_style= \"max-width:90%; height:auto;\" > or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+3 ALIGN=MIDDLE  ALT=\"x+=+3\"   DISABLED_style= \"max-width:90%; height:auto;\" > Discard the negative solution as lengths are positive.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+3 ALIGN=MIDDLE  ALT=\"x+=+3\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2B1+=+4 ALIGN=MIDDLE  ALT=\"x%2B1+=+4\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "The two legs are 3 inches and 4 inches. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );