document.write( "Question 225103: i have eight more quarters than dimes. if the coins are woth $6.20, how many dimes are there? \n" ); document.write( "

Algebra.Com's Answer #168043 by LtAurora(115) $\"\"$ $\"About$

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Our given equations are:
\n" ); document.write( " $\"Q=8%2BD\"$
\n" ); document.write( " $\".25Q%2B.1D=6.20\"$
\n" ); document.write( "Plug the first eq. into the second:
\n" ); document.write( " $\".25%288%2BD%29%2B.1D=6.2\"$
\n" ); document.write( "Simplify:
\n" ); document.write( " $\"2%2B.25D%2B.1D=6.2\"$
\n" ); document.write( "Move the 2 over and combine like terms:
\n" ); document.write( " $\".35D=4.2\"$
\n" ); document.write( "Divide both sides by .35:
\n" ); document.write( " $\"D=12\"$
\n" ); document.write( "So, using our first equation:
\n" ); document.write( " $\"Q=8%2B12\"$
\n" ); document.write( " $\"Q=20\"$
\n" ); document.write( "Checking our work: 20 quarters = $5 and 12 dimes = $1.20. The sum of those is $6.20, so we're good. \n" ); document.write( "

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