document.write( "Question 29995: Could you please help me with this problem \r
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\n" ); document.write( "\n" ); document.write( "Solve for x\r
\n" ); document.write( "\n" ); document.write( "\"+x+over+x%5E2+-8\" = 2 over x
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Algebra.Com's Answer #16802 by sdmmadam@yahoo.com(530)\"\" \"About 
You can put this solution on YOUR website!
x over x^2 -8}}} = 2 over x\r
\n" ); document.write( "\n" ); document.write( "x/(x^2-8) = 2/x ----(1)
\n" ); document.write( "Multiplying by x(x^2-8)
\n" ); document.write( "xX(x) = 2(x^2-8)
\n" ); document.write( "x^2= 2x^2-16
\n" ); document.write( "16 = 2x^2-x^2
\n" ); document.write( "16 =x^2
\n" ); document.write( "That is x^2 = 16
\n" ); document.write( "Taking square root
\n" ); document.write( "Therefore x = +4 or -4
\n" ); document.write( "Answer: x = 4 and x=-4
\n" ); document.write( "Verification: Both the values hold in (1).
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