document.write( "Question 224992: The length of a rectangle is 6 yards longer than triple the width. I f the perimeter of the rectangle is 340 yards, what are its dimensions \n" ); document.write( "

Algebra.Com's Answer #167993 by LtAurora(115) $\"\"$ $\"About$

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Perimeter is:
\n" ); document.write( " $\"2L%2B2W=340\"$
\n" ); document.write( "From the relation given we can write:
\n" ); document.write( " $\"L=3W%2B6\"$
\n" ); document.write( "Plug this back into the initial equation:
\n" ); document.write( " $\"2%283W%2B6%29%2B2W=340\"$
\n" ); document.write( "Simplify:
\n" ); document.write( " $\"6W%2B12%2B2W=340\"$
\n" ); document.write( "Combine like terms:
\n" ); document.write( " $\"8W%2B12=340\"$
\n" ); document.write( "Move the 12 to the other side:
\n" ); document.write( " $\"8W=328\"$
\n" ); document.write( "Divide both sides by 8:
\n" ); document.write( " $\"W=41\"$
\n" ); document.write( "Plug this back into our relation to determine L:
\n" ); document.write( " $\"L=3%2A41%2B6\"$
\n" ); document.write( " $\"L=129\"$
\n" ); document.write( "We can check this by adding our sides to determine the perimeter is 340:
\n" ); document.write( " $\"129%2B129%2B41%2B41=340\"$ , so we are correct. \n" ); document.write( "

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